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Title: Furin cleavage activates the epithelial Na+ channel by relieving Na+ self-inhibition. Author: Sheng S, Carattino MD, Bruns JB, Hughey RP, Kleyman TR. Journal: Am J Physiol Renal Physiol; 2006 Jun; 290(6):F1488-96. PubMed ID: 16449353. Abstract: Epithelial Na+ channels (ENaC) are inhibited by extracellular Na+, a process referred to as Na+ self-inhibition. We previously demonstrated that mutation of key residues within two furin cleavage consensus sites in alpha, or one site in gamma, blocked subunit proteolysis and inhibited channel activity when mutant channels were expressed in Xenopus laevis oocytes (Hughey RP, Bruns JB, Kinlough CL, Harkleroad KL, Tong Q, Carattino MD, Johnson JP, Stockand JD, and Kleyman TR. J Biol Chem 279: 18111-18114, 2004). Cleavage of subunits was also blocked by these mutations when expressed in Madin-Darby canine kidney cells, and both subunit cleavage and channel activity were blocked when wild-type subunits were expressed in furin-deficient Chinese hamster ovary cells. We now report that channels with mutant alpha-subunits lacking either one or both furin cleavage sites exhibited a marked enhancement of the Na+ self-inhibition response, while channels with a mutant gamma-subunit showed a modestly enhanced Na+ self-inhibition response. Analysis of Na+ self-inhibition at varying [Na+] indicates that channels containing mutant alpha-subunits exhibit an increased Na+ affinity. At the single-channel level, channels with a mutant alpha-subunit had a low open probability (P(o)) in the presence of a high external [Na+] in the patch pipette. P(o) dramatically increased when trypsin was also present, or when a low external [Na+] was in the patch pipette. Our results suggest that furin cleavage of ENaC subunits activates the channels by relieving Na+ self-inhibition and that activation requires that the alpha-subunit be cleaved twice. Moreover, we demonstrate for the first time a clear relationship between ENaC P(o) and extracellular [Na+], supporting the notion that Na+ self-inhibition reflects a P(o) reduction due to high extracellular [Na+].[Abstract] [Full Text] [Related] [New Search]