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  • Title: Spontaneous fluctuations of potassium channels in the apical membrane of frog skin.
    Author: Van Driessche W, Zeiske W.
    Journal: J Physiol; 1980 Feb; 299():101-16. PubMed ID: 6247479.
    Abstract:
    1. The previously demonstrated K+-dependent short-circuit current through the skin of frog species Rana temporaria (Zeiske & Van Driessche, 1979), bathed with mucosal K+- and serosal Na+-Ringer solution, was investigated with current-fluctuation analysis. 2. The current-noise spectra were recorded in the frequency range from 1 to 800 Hz and showed a Lorentzian component with a mean plateau value S0 = (1.50 +/- 0.05).10(-20) A2.s.cm-2 and a corner frequency of fc=(81.0 +/- 3.4)Hz(n=14). 3. S0 increased with mucosal K+ concentration, [K]o, while fc remained almost unchanged. A decrease in S0 was observed when serosal Na+ was replaced by K+. 4. Mucosal Cs+ (10 mM) depressed, reversibly, the K+-dependent current noise to the level of the background noise. Moreover, a linear decrease in fc with increasing Cs+ concentration was observed. 5. Among the other tested alkali cations, Rb+ was the only blocker though less potent than Cs+. Tetraethylammonium, 4-aminopyridine, 2.4.6-triaminopyrimidine and amiloride had no effect. 6. Alterations in the transcellular transport of Na+ contained in a mucosal solution with high [K]o resulted in significant changes in K+ current noise. 7. The current-fluctuation intensities decreased with increasing contact time to high [K]o; these changes were concomitant with the previously reported time dependence of the short-circuit current (Zeiske & Van Driessche, 1979). 8. The K+-dependent fluctuations are thought to originate from K+-selective pathways in the apical cell membranes. The description of the K+-current noise by a single Lorentzian suggests that the "K+ channels" switch randomly between an open and closed state. 9. Assuming a two state model for the channel-kinetics, the single channel current i and the channel density M were calculated as i=(0.37 +/- 0.05)pA and M=(0.53 +/- 0.08) mu-2 (n=13).
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